Respuesta :

1) To evaluate the following logarithm:

[tex]\log _72[/tex]

Given:

[tex]\log _74\approx0.712\text{ and }\log _78\approx1.069[/tex]

2) Notice that we can rewrite that log of 4 this way, using the quotient property of logarithms:

[tex]\begin{gathered} \log _7(\frac{8}{4})=\log _78-\log _74=\log _72 \\ 1.069\text{ -}0.712\text{ = }0.357 \\ \log _72\approx0.3567 \end{gathered}[/tex]

As we know that 8/4 =2, we could rewrite that as above.

3) Hence, the answer is:

[tex]\begin{gathered} 1)\text{ }\log _72\text{ =}\log _7(\frac{8}{4}) \\ 2)\text{ }\log _72=\log _78-\log _74 \\ \end{gathered}[/tex]

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