The equation is:
[tex]y+3=\frac{1}{2}(x-6)[/tex]Explanation:Given that the line has slope of 1/2, and passes through th e point (6, -3), the equation in point-slope form is:
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ \\ \text{where} \\ x_1=6 \\ y_1=-3 \\ m=\frac{1}{2} \end{gathered}[/tex]This becomes:
[tex]\begin{gathered} y-(-3)=\frac{1}{2}(x-6) \\ \\ y+3=\frac{1}{2}(x-6) \end{gathered}[/tex]