Question

I just want to make sure I solved it correctly this is how the formula looks and 39200[(1+0.082/1)^1(5) / 0.082/1

Answer 1

Hello! Let's rewrite the formula below:

$A\text{ = }\frac{39200\lbrack(1+\frac{0.082}{1})^{1(5)}-1\text{\rbrack}}{\frac{0.082}{1}}$

First, we can simplify the fractions with 1 in the denominator:

$\begin{gathered} A\text{ = }\frac{39200\lbrack(1+0.082)^{1.(5)}-1\text{\rbrack}}{0.082} \\ \\ A\text{ = }\frac{39200[(1.082)^5-1\text{\rbrack}}{0.082} \\ \\ A\text{ = }\frac{39200\lbrack(\frac{541}{500})^5-1\text{\rbrack}}{\frac{41}{500}} \\ \\ A\text{ = }\frac{39200\lbrack\frac{541^5}{500^5}^{}-1\text{\rbrack}}{\frac{41}{500}} \\ \\ A\text{ = }\frac{39200.\frac{541^5}{500^5}^{}-39200\text{\rbrack}}{\frac{41}{500}} \\ \\ A\text{ = }\frac{39200.\frac{541^5}{500^4.500}^{}-39200\text{\rbrack}}{\frac{41}{500}} \\ \\ A\text{ = }\frac{392.\frac{541^5}{500^3.500.5}^{}-39200\text{\rbrack}}{\frac{41}{500}} \\ \\ A\text{ = (}98.\frac{541^5}{500^3.125.5}^{}-39200)divided\frac{41}{500} \\ \\ A\text{ = }\frac{98.\frac{541^5}{500^2.500.125.5}^{}-39200}{\frac{41}{500}} \\ \\ A\text{ = }\frac{49\frac{541^5}{500^2.(250.125.5)}^{}-39200}{\frac{41}{500}} \\ \\ A\text{ = }\frac{49\frac{541^5}{500.500.(156250)}^{}-39200}{\frac{41}{500}} \\ \\ A\text{ = }\frac{\frac{49.541^5}{250000.156250}^{}-39200}{\frac{41}{500}} \\ \\ A\cong230889.65 \\ \end{gathered}$