Question

What must be the acceleration of a train in order for it to stop from 11.4 seconds in a distance of 589 m? (Assume the train accelerates uniformly.) Round to 4 decimal places if necessary

Answer 1

ANSWER:

-9.0643 m/s²

STEP-BY-STEP EXPLANATION:

Given:

Distance (d) = 589 m

Time (t) = 11.4 sec

We can calculate the acceleration using the following formula:

$\begin{gathered} a=-\frac{2s}{t^2} \\ \\ \text{ We replacing} \\ \\ a=-\frac{2\cdot589}{11.4^2} \\ \\ a=-9.0643\text{ m/s}^2 \end{gathered}$

The deceleration of the train is equal to 9.0643 m/s²