.
The intersection of the Lines A and B creates a pair of equivalent angles
This means
[tex]\begin{gathered} \angle1=\angle4 \\ \angle3x+7=\angle6 \\ \angle2=\angle5 \\ \angle3=\angle4x+5 \end{gathered}[/tex]We can solve for x using the fact that the angles ∠3x + 7 and ∠3 form a linear pair. This gives us an equation and in it, we can substitute for ∠3 from the equations given above and solve the resulting equation for x.
(2).
We can solve for x using the fact that angles ∠3x + 7 and ∠3 form a linear pair. i.e .
[tex](3x+7)+\angle3=180^o[/tex]and since
[tex]\angle3=\angle4x+5[/tex]the above becomes
[tex](3x+7)+(4x+5)=180^o[/tex]Expanding the above gives
[tex]7x+12=180^o[/tex]Subtracting 12 from both sides gives
[tex]7x=168^o[/tex]Finally, dividing both sides by 7 gives
[tex]x=24.[/tex]which is our answer!
(3).
Since we know that
[tex]\angle3x+7=\angle6[/tex]We can find the value of angle 6 by substituting the value of 3 in the above equation. This gives
[tex]\begin{gathered} 3(24)+7=\angle6 \\ \end{gathered}[/tex][tex]\boxed{\angle6=79^o\text{.}}[/tex]which is our answer!