Question

For each equation, choose the statement that describes its solutiorIf applicable, give the solution.

Answer 1

Part A.

The equation is given by

$4(x+1)+x=3(x-2)+2$

By distributing the number form into the parenthesis on the left hand side and the number 3 into the parenthesis of the right hand side, we have

$4x+4+x=3x-6+2$

By combinig similar terms, we get

$5x+4=3x-4$

Then, by subtracting 3x to both sides, we have

$2x+4=-4$

and by subtracting 4 to both sides, we get

$2x=-8$

then, x is given by

$\begin{gathered} x=\frac{-8}{2} \\ x=-4 \end{gathered}$

Then, the solution for part A is x=-4.

Part B

In this case, the equatiion is

$5(2+v)-v=10+4(v+1)$

Then, by distributing the number 5 into the parenthesis and the number 4 into the parenthesis on the right hand side, we have

$10+5v-v=10+4v+4$

By combining similar terms, we have

$10+4v=14+4v$

and by subtracting 4v to both side, we have

$10=14$

which is an absurd result. Therefore, the answer for part B is. No solution