Question

Kai took five tests this semester. His scores are listed below. 92, 88, 90, 96, 84What is the mean absolute deviation of Kai's test scores?4.03.22.01.6

Answer 1

the mean can be calculate with this equation:

$m=\frac{x_1+x_2+\cdots}{n}$

So in our problem will be:

$\begin{gathered} m=\frac{92+88+90+96+84}{5} \\ m=90 \end{gathered}$