Given the equation:
[tex]s=\sqrt[]{24d}[/tex]Where d is the distance and (s) is the speed
We will find the value of (s) when d = 250 feet
So, substitute with d = 250, and solve for (s)
[tex]s=\sqrt[]{24\cdot250}=\sqrt[]{6000}\approx77.459667[/tex]Rounding to the nearest tenth
so, the answer will be:
Speed = s = 77.5 mi/hr