Answer:
C. –8, –6
Explanation:
Given the equation:
[tex]3x+4y=-24[/tex](a)x-intercept
The x-intercept is the value of x at which y=0.
When y=0:
[tex]\begin{gathered} 3x+4y=-24 \\ 3x+4(0)=-24 \\ 3x=-24 \\ \text{Divide both sides y 3} \\ \implies x=-\frac{24}{3} \\ x=-8 \end{gathered}[/tex]b)y-intercept
The y-intercept is the value of y at which x=0.
When x=0:
[tex]\begin{gathered} 3x+4y=-24 \\ 3(0)+4y=-24 \\ 4y=-24 \\ \text{Divide both sides by 4} \\ \implies y=-\frac{24}{4} \\ y=-6 \end{gathered}[/tex]The x– and y–intercepts of the line: 3x + 4y = –24 are –8 and –6.
Option C is correct.