Since the given equation is
[tex]V=\frac{1}{3}sh^2[/tex]We need to solve for each, then
We have to isolate h on one side and the other terms on the other side
Then multiply both sides by 3
[tex]\begin{gathered} (3)\times V=\frac{1}{3}\times(3)sh^2 \\ 3V=sh^2 \end{gathered}[/tex]Now, divide both sides by s
[tex]\begin{gathered} \frac{3V}{s}=\frac{sh^2}{s} \\ \frac{3V}{s}=h^2 \\ h^2=\frac{3V}{s} \end{gathered}[/tex]Take a square root for both sides
[tex]\begin{gathered} \sqrt[]{h^2}=\pm\sqrt[]{\frac{3V}{s}} \\ h=\pm\sqrt[]{\frac{3V}{s}} \end{gathered}[/tex]