Recall that given a line with equation
[tex]y=mx+b[/tex]
A line perpendicular to that equation can be determined by getting the negative reciprocal of the equation
[tex]y=-\frac{1}{m}+b[/tex]
Given the equation y = -5x + 4, the slope of the line is -5, get the negative reciprocal and we have
[tex]-\frac{1}{m}=-\frac{1}{-5}=\frac{1}{5}[/tex]
We should have an equation with a slope of 1/5, this is represented therefore by the equation
[tex]y=\frac{1}{5}x-1\text{ \lparen final answer\rparen}[/tex]
