Given:
The coefficient of friction, μ=0.37
The mass of the box, m=8 kg
The force applied to the box, F=32 N
To find:
The acceleration of the box.
Explanation:
The net force acting on the box is given by,
[tex]\begin{gathered} F_n=F-f \\ =F-mg\mu \end{gathered}[/tex]
Where g is the acceleration due to gravity.
On substituting the known values,
[tex]\begin{gathered} F_n=32-8\times9.8\times0.37 \\ =2.992\text{ N} \\ \approx3\text{ N} \end{gathered}[/tex]
From Newton's second law, the net force acting on the object is given by,
[tex]F_n=ma[/tex]
Where a is the acceleration of the object.
On substituting the known values,
[tex]\begin{gathered} 3=8\times a \\ \Rightarrow a=\frac{3}{8} \\ =0.375\text{ m/s}^2 \end{gathered}[/tex]
Final answer:
The acceleration of the box is 0.375 m/s²
