A = (-1, 5) = (x1, y1)
B = (0,8) = (x2, y2)
Using the distance formula:
[tex]\begin{gathered} d^2={\left({x}_2-{x}_1\right)}^2+{\left({y}_2-{y}_1\right)}^2\Rightarrow d=\sqrt{{\left({x}_{2}-{x}_{1}\right)}^{2}+{\left({y}_{2}-{y}_{1}\right)}^{2}} \\ d=\sqrt{(0--1)^2+(8-5)^2} \\ d=\sqrt{1^2+3^2}=\sqrt{1+9}=\sqrt{10} \\ d=3.162 \end{gathered}[/tex]
