Given:
The velocity of meteorite is
[tex]\begin{gathered} v=\frac{11.2km}{s} \\ =11.2\times1000\text{ m/s} \\ =11200\text{ m/s} \end{gathered}[/tex]The mass of the meteorite is
[tex]m\text{ = 2.3}\times1^{}0^5kg[/tex]To find the kinetic energy of the meteorite.
Explanation:
The kinetic energy is calculated by the formula
[tex]K\mathrm{}E\text{. =}\frac{1}{2}mv^2[/tex]On substituting the values, the kinetic energy will be
[tex]\begin{gathered} K\mathrm{}E\text{. = }\frac{1}{2}\times2.3\times10^5\times(11200)^2 \\ =1.44\text{ }\times10^{13}\text{ J} \end{gathered}[/tex]Final Answer: The kinetic energy of the meteorite is 1.44 x 10^(13) J.