we divide the pentagon into two figures
Trapezium
trapezium area
[tex]\begin{gathered} A=\frac{(B+b)\times h}{2} \\ \\ A=\frac{(6+2)\times4}{2} \\ \\ A=16 \end{gathered}[/tex]
the are of the trapezium is 16 square in
Triangle
triangle area
[tex]\begin{gathered} A=\frac{b\times h}{2} \\ \\ A=\frac{6\times3}{2} \\ \\ A=9 \end{gathered}[/tex]
the area of the triangle is 9 square in
Total area
Sum the areas to find the area of the pentagon
[tex]\begin{gathered} 16+9 \\ =25 \end{gathered}[/tex]
the pentagon area is 25 square inches
