Question

How does g(x)= 2.10 change over the interval from x2 to x - 37g(x) decreases by 10g(x) Increases by a factor of 10g(x) decreases by a factor of 10g(x) increases by 1,000%

Answer 1

we are given the function

$g(x)=2\cdot10^x$

we want to check how the function changes from x=2 to x=3. We will calculate

$\frac{g(3)}{g(2)}$

to check how it changed. So we have

$\frac{g(3)}{g(2)}=\frac{2\cdot10^3}{2\cdot10^2}=10^{3\text{ -2}}=10$

which means that g increases by a factor of 10