Respuesta :

Consider that the two events (tossing a coin and spinning a spinner) are independent and that the probability of landing on blue is equal to 1/3; thus,

[tex]\begin{gathered} P(heads\&no-blue)=\frac{1}{2}\cdot(1-\frac{1}{3}) \\ \Rightarrow P(heads\&no-blue)=\frac{1}{2}\cdot\frac{2}{3}=\frac{1}{3} \end{gathered}[/tex]

Thus, the answer is P(heads&NoBlue)=1/3

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