find the for (f/g)(x) and simplify the answer .then find the domain for (f/g)(x) then round answer to two decimal places if necessary

Answer:
[tex]\begin{gathered} \frac{f(x)}{g(x)}=\frac{5x\cdot\sqrt[]{x-1}}{x-1} \\ \text{Domain(f/g)(x)}=x>1\text{ or (1,}\infty) \end{gathered}[/tex]Step by step explanation:
We have to find the division of the functions:
[tex]\begin{gathered} f(x)=5x \\ g(x)=\sqrt[]{x-1} \\ (\frac{f}{g})(x)=\frac{f(x)}{g(x)} \end{gathered}[/tex]Then, by the division we get:
[tex]\frac{f(x)}{g(x)}=\frac{5x}{\sqrt[]{x-1}}[/tex]To solve the division, we have to multiply by the conjugated:
[tex]\begin{gathered} \frac{f(x)}{g(x)}=\frac{5x\cdot\sqrt[]{x-1}}{\sqrt[]{x-1}\cdot\sqrt[]{x-1}} \\ \frac{f(x)}{g(x)}=\frac{5x\cdot\sqrt[]{x-1}}{x-1} \end{gathered}[/tex]Since the function can only take a number greater than 1 because we need a number different from zero on the denominator and no negative values on the roots.