Given the equations:
8x - 6y = 6 ...........................1
-212x + 9y = 18.......................2
Let's use substitution method to solve this.
Using equation 1:
8x - 6y = 6
Add 6y to both sides:
8x - 6y + 6y = 6 + 6y
8x = 6 + 6y
Divide through by 8:
[tex]\begin{gathered} \frac{8x}{8}=\frac{6}{8}+\frac{6y}{8} \\ \\ x\text{ = }\frac{3}{4}+\frac{3}{4}y\ldots\ldots\ldots\ldots\ldots\ldots\ldots.3 \end{gathered}[/tex]Substitute equation 3 into equation 1:
[tex]\begin{gathered} 8(\frac{3}{4}+\frac{3}{4}y)\text{ - 6y = 6} \\ \\ 6\text{ + 6y - 6y = 6} \\ \\ 6\text{ = 6} \end{gathered}[/tex]6 = 6
Since the right side of the equation equals the left side, the system has infinitely many solutions.
ANSWER:
Infinite number of solutions