Given,
The frequency of the source, f=1216 Hz
The speed with which the car is moving away from the source, vā=28 m/s
The speed of the sound, v=343 m/s
The frequency with which the observer hears the sound is given by,
[tex]f_0=\frac{v-v_0}{v}f[/tex]On substituting the known values,
[tex]\begin{gathered} f_0=\frac{343-28}{343}\times1216 \\ =1116.7\text{ Hz} \\ \approx1117\text{ Hz} \end{gathered}[/tex]Thus the frequency heard by the observer is 1117 Hz. Therefore the correct answer is option 4.