Answer:
We first look up in the periodic table the molar mass of each individual element:
Fe: 55.84 g/mol
Cl: 35.45 g/mol
Then we calculate the molar mass of the compound:
[tex]\rbrack M_{FeCl_3}=M_{Fe}+3.M_{Cl}=55.84\frac{g}{mol}+3.(35.45\frac{g}{mol})=162.19\frac{g}{mol}[/tex]Finaly we calculate the percentage:
[tex]\begin{gathered} Fe=\frac{55.84\frac{g}{mol}}{162.19\frac{g}{mol}}x100=34.4\% \\ Cl=\frac{3.\text{ }35.45\frac{g}{mol}}{162.19\frac{g}{mol}}x100=65.6\% \end{gathered}[/tex]So finally, the percentages of each element in the molecule are:
Fe: 34.4%
Cl: 65.6%