Given
a = 10 in
c = 26 in
b = ?
Procedure
Pythagorean theorem, the well-known geometric theorem that the sum of the squares on the legs of a right triangle is equal to the square on the hypotenuse (the side opposite the right angle)—or, in familiar algebraic notation, a2 + b2 = c2.
[tex]\begin{gathered} b=\sqrt[]{c^2-a^2} \\ b=\sqrt[]{26^2-10^2} \\ b=\sqrt[]{676-100} \\ b=\sqrt[]{576} \\ b=24 \end{gathered}[/tex]The answer would be b = 24.
