Question

Write a balanced reaction for which the following rate relationships are true.ANORate =ON+0₂-NO0240+24+02₂ONO+№+20₂ONO+№₂+0₂02M₂+0₂-24₂02 At1 A/N2 At4/0₂]At

Answer 1

Answer:

$2N_2O\rightarrow2N_2+O_2$

Explanations:

Given the general reaction expressed as:

$aA+bB\rightarrow cC+dD$

The equivalent rate of reaction is given as;

$-\frac{1}{a}\frac{\triangle[A]}{\triangle[t]}=-\frac{1}{b}\frac{\triangle{[B]}}{\triangle[{t}]}=\frac{1}{c}\frac{\triangle{[C]}}{\triangle[{t}]}=\frac{1}{d}\frac{\triangle{[D]}}{\triangle[{t}]}$

Note that the reciprocal of the coefficient at the reactant are negated.

Given the rate relationship;

$-\frac{1}{2}\frac{\triangle[N_2O]}{\triangle{[t}]}=\frac{1}{2}\frac{\triangle{[N_2]}}{\triangle{[t}]}=\frac{1}{1}\frac{\triangle[O_2]}{\triangle[{t]}}$

This shows that the compound at the reactant is N2O with a coefficient of 2 while the elements at the product side are N2 and O2 respectively.

$2N_2O\rightarrow2N_2+O_2$

This gives the equaivalent chemical reaction