Question

true or false18. In the circle: x2+(y-2)2=12, the radius is 12

Answer 1

ANSWER

False

EXPLANATION

The equation of a circle is:

$(x-x_0)^2+(y-y_0)^2=r^2$

Where (x0, y0) is the center of the circle and r is the radius.

If we have the equation of a circle:

$x^2+(y-2)^2=12$

x0 = 0 and y0 = 2. Therefore the center of the circle is at point (0, 2). Also, we have that:

$r^2=12$

Solving for r, the radius of this circle is:

$r=\sqrt[]{12}$

Therefore, it is false that the radius of the given circle is 12.