ANSWER
The common ratio is 3/2.
EXPLANATION
Given:
[tex]\begin{gathered} \text{ 2nd term of GP: ar = -4} \\ \text{ 5th term of GP: ar}^4\text{ = -}\frac{27}{2} \end{gathered}[/tex]Desired Outcome:
Common ratio
Determine the common ratio
ar = -4
a = -4/r
[tex]\begin{gathered} substitute\text{ a} \\ ar^4\text{ = -}\frac{27}{2} \\ (-\frac{4}{r})r^4\text{ = -}\frac{27}{2} \\ -4r^3\text{ = -}\frac{27}{2} \\ divide\text{ bothe sides by -4} \\ r^3\text{ = }\frac{27}{8} \\ take\text{ cube root of both sides} \\ r^3\text{ = }\frac{3^3}{2^3} \\ r\text{ = }\frac{3}{2} \end{gathered}[/tex]Hence, the common ratio of the geometric sequence is 3/2.