Question 4.
From the answers in part 1 and part 2, we have:
• Equation for the wallpaper of family room:
[tex]y=21x^2-21[/tex]
• Equation for the wallpaper of the living room:
[tex]y=16x^2[/tex]
Let's solve for the following:
• (a) Area of the living room when x = 8
Substitute 8 for x in the second equation which represents the area of the living room and evaluate:
[tex]\begin{gathered} y=16x^2 \\ \\ y=16(8)^2 \\ \\ y=16(64) \\ \\ y=1024ft^2^{} \end{gathered}[/tex]
When x = 8, the area of the living room is 1024 square feet.
• (b). Area of the family room when x = 8.
Substitute 8 for x in the first equation which represents area of the familiy room and evaluate
[tex]\begin{gathered} y=21x^2-21 \\ \\ y=21(8)^2-21 \\ \\ y=21(64)-21 \\ \\ y=1344-21 \\ \\ y=1323ft^2 \end{gathered}[/tex]
When x = 8, the area of the family room is 1323 square feet.
• (c). Let's determine how much more square feet the living room will require.
Area of family room - area of living room = 1323 square feet - 1024 square feet = 299 square feet.
Therefore, you will need 299 more square feet of wallpaper for the living room than the family room