Question

a farther walks 36 miles in 12 hours while his son covers the same distance on a bicycle at twice the fathers rate of speed at this rate how many miles would the bicycle rider travel in 9 hours

Answer 1

To solve this problem, first, let's find the speed of the father.

Let x be the speed of the father.

The speed is distance/time.

Then,

$Speed=\frac{36}{12}=3\text{ }\frac{miles}{hours}$

Second, let's find the speed of the soon.

Let y represent the speed of the soon.

Since the speed is twice the speed of the father:

y = 2x:

$\begin{gathered} y=2*3 \\ y=6\text{ }\frac{miles}{hour} \end{gathered}$

Finally, find the distance traveled in 9 hours.

The distance is the product of the time and the speed:

$\begin{gathered} distance=9*6 \\ distance=54\text{ }miles \end{gathered}$

Answer: 54 miles.