1) Balance the chemical equation
[tex]3N_2H_4(l)\rightarrow4NH_3(g)+N_2(g)[/tex]
2) Convert grams of N2H4 into moles of N2H4.
The molar mass of N2H4 is 32.04516 g/mol
[tex]\text{mol }N_2H_4=61.3gN_2H_4\cdot\frac{1molN_2H_4}{32.04516gN_2H_4}=1.912925molN_2H_4[/tex]
3) Moles of NH3 produced from 1.912925 mol N2H4
3 N2H4: 4 NH3
[tex]\text{mol NH}_3=1.912925molN_2H_4\cdot\frac{4molNH_3}{3molN_2H_4}=2.55057molNH_3[/tex]
61.3 g N2H4 can produce 2.55 mol NH3.
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