Question

I need help on this and I don’t think my answer is correct. Please help.

Answer 1

we have the function

$f(x)=\frac{1}{2}x+8$

Make a table

For each value of x, substitute in the given function to obtain the value of f(x)

For x=0

$f(x)=\frac{1}{2}(0)+8=8$

For x=1

$f(x)=\frac{1}{2}(1)+8=\frac{17}{2}$

For x=2

$f(x)=\frac{1}{2}(2)+8=9$

For x=3

$f(x)=\frac{1}{2}(3)+8=\frac{19}{2}$

For x=4

$f(x)=\frac{1}{2}(4)+8=10$

For x=5

$f(x)=\frac{1}{2}(5)+8=\frac{21}{2}$

For x=6

$f(x)=\frac{1}{2}(6)+8=11$