Question

I need this problem from my prep guide answered, it has four answer options and I will provide another picture with the rest of the answer optionsThe subject is pre-Calc

Answer 1

Given,

The equation of circle is,

$(x+1)^2+(y+3)^2=16$

The standard equation of cicle is,

$(x-h)^2+(y-k)^2=r^2$

Where, (h,k) is the center of the circle and r is the radius of the circle.

On compring the standard equation of circle with given equation then,

$(h,k)=(-1,-3)$

Both the coordinates of the center of the circle is negative. Thus, lies in the third quadrant.

Here, the circle of option A has its center at third quadrant.

Hence, option A is correct.