Using cross multiplication,
[tex](x+1)\cdot5=(x+2)\cdot3[/tex]Applying distributive property,
[tex]\begin{gathered} 5x+5\cdot1=3x+2\cdot3 \\ 5x+5=3x+6 \end{gathered}[/tex]Subtracting 5 and 3x at both sides,
[tex]\begin{gathered} 5x+5-5=3x+6-5 \\ 5x=3x-1 \\ 5x-3x=3x-1-3x \\ 2x=1 \end{gathered}[/tex]Dividing by 2 at both sides,
[tex]\begin{gathered} \frac{2x}{2}=\frac{1}{2} \\ x=\frac{1}{2} \end{gathered}[/tex]