Respuesta :
We have and equation for hearing loss:
[tex]\begin{gathered} y=0.0086x^2-0.4267x+6.6434 \\ \text{Where x is the age and y the percent of hearing loss} \end{gathered}[/tex]1. We want to know the percent of hearing loss at 18 years old, so we have to evaluate the equation at x=18:
[tex]y(18)=0.0086\cdot18^2-0.4267\cdot18+6.6434=1.7492[/tex]2. We want to find the percent range of hearing loss for the 30 - 60 years all. To do this we need to find the minimum and maximun of the equation at x between [30,60].
First we know the equation is a parabola, so we can find the minimun of the parabola, this is the vertex:
[tex]\begin{gathered} \text{General equation of a parabola is:} \\ y=ax^2+bx+c \\ x_{\text{vertex}}=-\frac{b}{2a},y_{\text{vertex}}=y(x_{\text{vertex}}) \end{gathered}[/tex]In this case, a=0.0086, b=-0.4267 and c=6.6434:
[tex]\begin{gathered} x_{\text{vertex}}=-\frac{(-0.4267)}{2\cdot0.0086}=\frac{0.4267}{2\cdot0.0086}=24.8 \\ y_{\text{vertex}}=0.0086\cdot24.8^2-0.4267\cdot24.8+6.6434=\text{1}.35 \end{gathered}[/tex]So, the minimun hearing loss is 1.35% at 24.8 years old, because 24.8 is not between 30 -60 years and it's less than 30, the minumun ot the range is in 30 years and the maximun at 60 years:
[tex]\begin{gathered} y(30)=0.0086\cdot30^2-0.4267\cdot30+6.6434=1.58 \\ y(60)=0.0086\cdot60^2-0.4267\cdot60+6.6434=12.0 \end{gathered}[/tex]So, the range of hearing loss is [1.58, 12.0] at ages 30-60 years.
3. This is the same as point 2, we already has the value for 60 years, so we need to evaluate the equation at 84 years:
[tex]y(84)=0.0086\cdot84^2-0.4267\cdot84+6.6434=31.48[/tex]The range of hearing loss is [12.0, 31.48] ar ages 60-84 years.
4. Now we want to find the values of x where the y < 5, so:
[tex]\begin{gathered} y=5=0.0086x^2-0.4267x+6.6434 \\ 0=0.0086x^2-0.4267x+6.6434-5 \\ 0=0.0086x^2-0.4267x+1.6434 \end{gathered}[/tex]Now we need to find the roots with the formula:
[tex]\begin{gathered} \text{General parabola form is:} \\ ax^2+bx+c \\ \text{and the roots are:} \\ x_{1,2}=\frac{-b\pm\sqrt[]{b^2-4\cdot a\cdot c}}{2a} \end{gathered}[/tex]In this case, a=0.0086, b=-0.4267 and c=1.6434
[tex]\begin{gathered} x_{1,2}=\frac{0.4267\pm\sqrt[]{(-0.4267)^2-4\cdot0.0086\cdot1.6434}}{2\cdot0.0086} \\ x_{1,2}=\frac{0.4267\pm0.3543}{0.0172} \\ x_1=\frac{0.4267+0.3543}{0.0172}=45.4 \\ x_2=\frac{0.4267-0.3543}{0.0172}=4.2 \end{gathered}[/tex]So, the people between 4.2 and 45.4 years has a hearing loss less than 5%.
