An ideal gas held at constant pressure has its temperature changed by a factor of 2.53x. By what factor does its volume increase or decrease?

Respuesta :

In order to calculate the change in volume, we can use the relation below:

[tex]\frac{P_iV_i}{T_i}=\frac{P_fV_f}{T_f}[/tex]

If the pressure remains the same and the temperature increases by 2.53x, we have:

[tex]\begin{gathered} \frac{P\cdot V_i}{T}=\frac{P\cdot V_f}{2.53T}\\ \\ V_i=\frac{V_f}{2.53}\\ \\ V_f=2.53V_i \end{gathered}[/tex]

Therefore the volume also changes by a factor of 2.53.

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