The perimeter of the given trapezium is the sum of the side lengths of the trapezium.
Hence, the perimeter P is,
[tex]P=18+10.9+6+6=40.9\text{ in}[/tex]Therefore, the perimeter P of the given trapezium is 40.9 in.
Given, the altitude of the trapezium, h=5.1 in.
The length of parallel sides,
a=6 in.
b=18 in.
The area A of the trapezium is,
[tex]\begin{gathered} A=\frac{1}{2}\times sum\text{ of parallel sides}\times altitude \\ =\frac{1}{2}\times(a+b)\times h \\ =\frac{1}{2}\times(6+18)\times5.1 \\ =61.2\text{ sq.in.} \end{gathered}[/tex]Therefore, area A of the trapezium is 61.2 sq.in.
