Respuesta :

[tex]x=9.3[/tex]

1) The best way to tackle this question is to sketch this out:

Note that, we need to know the height of that trapezoid. So, let's trace a parallel line from the vertex to the larger base of that trapezoid.

2) As we can see, we can now realize the existence of a right triangle, so let's make use of the Pythagorean Theorem to find a congruent side parallel to the height "x":

[tex]\begin{gathered} a^2=b^2+c^2 \\ 16^2=13^2+c^2 \\ 256=169+c^2 \\ 256-169=c^2 \\ 87=c^2 \\ c=\sqrt[]{87} \\ c\approx9.3 \end{gathered}[/tex]

Thus, that's the approximate measurement of x, to the nearest tenth.

Ver imagen MylenaH132471
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