Given:
Principal, P = $2,240
Interest rate, r = 3½% = 3.5% = 0.035
Time, t = 6 months = 6/12 months a year = 0.5 years
Yearly deposits, n = 4 (quaterly)
Use the compound interest formula below:
[tex]A\text{ = P(}1\text{ + }\frac{r}{n})^{nt}[/tex]Therefore, we have:
[tex]A\text{ = 2240(1 + }\frac{0.035}{4})^{4\cdot0.5}[/tex]Solving further,
[tex]A\text{ = 2240 (1 + }0.1757)[/tex][tex]\begin{gathered} A\text{ = 2240( 1.01757)} \\ \text{ = }2279.3715 \end{gathered}[/tex]Therefore his new balance after 6 months is $2279.37
ANSWER:
$2,279.37