Respuesta :

We need to find a perfect square from the expression

[tex]y^2-2y[/tex]

In this regard, we can note that

[tex](y-1)^2=y^2-2y+1[/tex]

Then, by comparing this result with our expression, we can see that the blank space is 1 because

[tex]y^2-2y+1=\left(y-1\right)^2[/tex]

Therefore, the answer is:

Ver imagen IosephH65572
ACCESS MORE
EDU ACCESS