We need to find a perfect square from the expression
[tex]y^2-2y[/tex]In this regard, we can note that
[tex](y-1)^2=y^2-2y+1[/tex]Then, by comparing this result with our expression, we can see that the blank space is 1 because
[tex]y^2-2y+1=\left(y-1\right)^2[/tex]Therefore, the answer is: