As the given equations are:
[tex]\begin{gathered} 4x-2y=8 \\ 2x+y=2 \end{gathered}[/tex]By simplifying the first equation:
[tex]2x-y=4[/tex]Now add the 3rd and 2nd equation:
[tex]\begin{gathered} (2x+y)+(2x-y)=2+4 \\ 4x=6 \\ x=\frac{6}{4} \\ x=\frac{3}{2} \end{gathered}[/tex]Now put the value of x in 2nd equation:
[tex]\begin{gathered} 2\times\frac{3}{2}+y=2 \\ 3+y=2 \\ y=-1 \end{gathered}[/tex]So there is only one solution (3/2, -1)