Solution:
Given that;
The area of the rectangular floor in Tamara's room is 95 5/6 square feet, i.e.
[tex]\begin{gathered} A=95\frac{5}{6}\text{ square feet} \\ A=\frac{575}{6}\text{ square feet} \end{gathered}[/tex]The width of the room is 8 1/3 feet, i.e.
[tex]\begin{gathered} w=8\frac{1}{3}\text{ feet} \\ w=\frac{25}{3}\text{ feet} \end{gathered}[/tex]To find the length, l, of the rectangular floor in Tamara's room, we will apply the formula to find the area, A, of a rectangle below,
[tex]\begin{gathered} A=lw \\ Where \\ l\text{ is the length} \\ w\text{ is the width} \end{gathered}[/tex]Substitute the values of the area and width into the formula above, to find the length as shown below
[tex]\begin{gathered} A=lw \\ \frac{575}{6}=l\times\frac{25}{3} \\ \frac{575}{6}=\frac{25l}{3} \\ Crssomultiply \\ 6\times25l=575\times3 \\ l=\frac{575\times3}{6\times25} \\ l=\frac{23}{2}\text{ feet} \\ l=11\frac{1}{2}\text{ feet} \end{gathered}[/tex]Hence, the length of tamara’s room is 11 1/2 feet
