Given:
[tex]h(x)=x^2-1[/tex]
Required:
To calculate which option is correct
Explanation:
According to the formula for the average rate of change of the function:
[tex]\begin{gathered} \frac{\Delta y}{\Delta x}=(f^1(x_1)+f^1(x_2))\text{ divide by 2} \\ \\ So,\text{ -3}\leq x\leq1,\frac{\Delta y}{\Delta x}=\frac{-6+2}{2}=-2 \\ \\ it\text{ has a negative rate of change.} \end{gathered}[/tex]
Required answer:
Option C
