Question

I'm trying to slove this problem but I need some help answering it

Answer 1

Given:

m = 2 x 10^6 kg

v = 93 m/s

SA wings = 1600 m^2

Pressure below - pressure above = weight / Area

P - P' = mg / A

Apply Bernoulli's principle:

P + 1/2 dv^2 = P' + 1/2 d v'^2

P-P' = 1/2 dv'^2 - 1/2dv^2

mg/A = 1/2 d (v'^2 - v^2 )

d = density of air = 1.225 kg/m^3

g = gravity = 9.8 m/s^2

Replacing:

$\frac{(2x10^{^6})(9.8)}{1600}=\frac{1}{2}(1.225)(v^{\prime2}-93)$

Solve for v'

12,250 = 0.6125 (v'^2 - 93 )

12,250 /0.6125 = v'^2-93

20,000+93 = v'^2

√20,093 = v'

v' = 141.74 m/s = 142 m/s