First, we need to test two scenarios using the sphere volume formula:
The volume for a sphere is given by:
[tex]A_s=\frac{4}{3}\pi r^3[/tex]Let us set r=3
Then:
[tex]\begin{gathered} A_{s}=\frac{4}{3}\pi r^{3} \\ A_s=\frac{4}{3}\pi(3)^3 \\ A_s=36\pi \\ A_s=113.04 \end{gathered}[/tex]If we tripled the radio= 3r = 3(3)= 9. Then:
[tex]\begin{gathered} A_s=\frac{4}{3}\pi(9)^3 \\ A_s=3052.08 \end{gathered}[/tex]Now, we need to compare both results:
A1 = 113.14
A2 = 3052.08
If we multiply A1 by 27=
27(113.14) = 3052.08
Hence, the volume when the radius is tripled is the product of the first volume by 27.
Therefore, the correct answer is option D.It is 27 times larger