A BMX biker leaves the end of a horizontal ledge with a velocity of 27 m/s and lands 7.2 m from the base of the ledge. How high is the ledge?

Respuesta :

Given data

*The given velocity of the BMX biker is u = 27 m/s

*The horizontal range from the base of the ledge is R = 7.2 m

The formula for the time taken by the BMX bike is to reach 7.2 m from the base of the ledge is given by the relation as

[tex]\begin{gathered} R=ut \\ t=\frac{R}{u} \end{gathered}[/tex]

Substitute the known values in the above expression as

[tex]\begin{gathered} t=\frac{7.2}{27} \\ =0.26\text{ s} \end{gathered}[/tex]

The formula for the height of the ledge is given by the equation of motion as

[tex]h=\frac{1}{2}gt^2[/tex]

Substitute the known values in the above expression as

[tex]\begin{gathered} h=\frac{1}{2}\times9.8\times(0.26)^2 \\ =0.33\text{ m} \end{gathered}[/tex]

Hence, the height of the ledge is h = 0.33 m

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