Answer:
7/32
Explanation:
The seventh-grade class has 7 girls and 1 boy.
[tex]P(\text{selecting a girl from seventh grade)}=\frac{7}{7+1}=\frac{7}{8}[/tex]The eighth-grade class has 3 girls and 9 boys.
[tex]P(\text{selecting a girl from eighth grade)}=\frac{3}{3+9}=\frac{3}{12}[/tex]Therefore, the probability that the students she selects are both girls:
[tex]P(\text{both are girls)}=\frac{7}{8}\times\frac{3}{12}=\frac{7}{32}[/tex]The probability is 7/32.
