Question

how do I solve and what would be the answer

Answer 1

Given

The area of the rectangle is represented as,

$A=14x^3-35x^2+42x$

And, the length is represented as,

$l=7x$

To find the breadth of the rectangle.

Now,

The area of the rectangle is given by,

$A=l\times b$

Then,

$b=\frac{A}{l}$

Substitute the values of A and l in the above equation.

Then,

$b=\frac{14x^3-35x^2+42x}{7x}$

Since the common terrm in 14x^3-35x^2+42x is 7x.

Then,

$\begin{gathered} b=\frac{7x(2x^2-5x+6)}{7x} \\ b=2x^2-5x+6 \end{gathered}$

Hence, the breadth of the rectangle is 2x^2-5x+6.