Question

4х + 5y = 19 8х - бу = -10

Answer 1

$\text{x = 1, y = 3}$

Here, we want to solve the system of linear equations simultaneously

We start by multiplying the first equation by 2 and the second by 1

$\begin{gathered} 8x\text{ + 10y = 38} \\ 8x-6y\text{ = -10} \end{gathered}$

We can now proceed to subtract the second equation from the first

That will give;

$\begin{gathered} (8x-8x)+(10y-(-6y))\text{ = 38-(-10)} \\ 16y\text{ = 48} \\ y\text{ = }\frac{48}{16} \\ y\text{ = 3} \end{gathered}$

To get the value of x, we will need to substitute the calculated value of y into any of the two initial equations

Thus, we have it that;

$\begin{gathered} 4x\text{ + 5(3) = 19} \\ 4x\text{ + 15 = 19} \\ 4x\text{ = 19-15} \\ 4x\text{ = 4} \\ \text{ x = }\frac{4}{4} \\ x\text{ = 1} \end{gathered}$