Question

2) Letter tiles similar to the example here are placed in a bag. There are a total of 8 tiles in the bag containing the following letters: G, I, R, V, I, A, I and N a) What is the probability of selecting an 1, keeping it, then an A?

Answer 1

3/56

Explanation:

Total tiles = 8

Number of is in G, I, R, V, I, A, I, N = 3

Probability of selecting I = number of Is/total tiles

$\text{Probability of selecting I = }\frac{3}{8}$

After selecting I, it is kept before picking A

This means we are picking A without replacing I

$\begin{gathered} \text{Probability of picking A = number of As/total tiles} \\ \text{Probability of picking A =}\frac{1}{8} \\ \\ \text{SInce I, is not replaced, the total tiles left = 7} \\ \text{Probability of picking A will be = }\frac{1}{7} \end{gathered}$

Probability of selecting an I, keeping it, then an A:

$\begin{gathered} =\frac{3}{8}\times\frac{1}{7} \\ =\text{ 3/56} \end{gathered}$