Question

working on a practice test and need a little support on a few

Answer 1

Solution

For this case we can use the following formula:

$V=\frac{1}{3}\pi\cdot r^2\cdot h$

And we have that :

r= 8/2= 4in

h = 12 in

Replacing we got:

$V=\frac{1}{3}\pi\cdot(4)^2\cdot12=201.06$

then the answer is :

V= 201.06

For the second case we can do this:

2x +35= 5x-22

35+22 = 5x-2x

57 = 3x

x= 57/3= 19