Respuesta :

Starting with the equation:

[tex]2-\ln (x+3)=\ln (4)[/tex]

Add ln(x+3) to both sides:

[tex]2=\ln (4)+\ln (x+3)[/tex]

Use the property:

[tex]\ln (a)+\ln (b)=\ln (a\cdot b)[/tex]

to rewrite the right hand side of the equation:

[tex]2=\ln (4(x+3))[/tex]

Use the distributive property to rewrite 4(x+3) as 4x+12:

[tex]2=\ln (4x+12)[/tex]

Use the property:

[tex]a=b\Rightarrow c^a=c^b[/tex]

for a=2, b=(4x+12) and c=e:

[tex]e^2=e^{\ln (4x+12)}[/tex]

Use the property:

[tex]e^{\ln (a)}=a[/tex]

to rewrite the right hand side of the equation:

[tex]e^2=4x+12[/tex]

Substract 12 from both sides of the equation:

[tex]e^2-12=4x[/tex]

Divide both sides by 4:

[tex]\frac{e^2}{4}-3=x[/tex]

Substitute the value of x into the original equation to check the answer.

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