Consider ADEF with vertices D(-6,4) E(0,8), and F(2,-2) Find the coordinates of the vertices of the final image of ADEF after the similarity transformation Translation: (x,y) - (x + 8y + 4) Dilation: (x,y)-(1/2x, 1/2y) centered at (0,0) The coordinates of the vertices of the final image are D'' E" and F"

Consider ADEF with vertices D64 E08 and F22 Find the coordinates of the vertices of the final image of ADEF after the similarity transformation Translation xy x class=

Respuesta :

D''(1, 4), E"(4, 6) and F"​(5, 1)

Explanation:

Coordinates of original image: D(-6,4), E(0,8) and F(2,-2)

Translation: (x,y) to (x + 8, y + 4)

The coordinate becomes:

D(-6,4) = (-6+8, 4+4) = (2, 8)

E(0,8) = (0+8, 8+4) = (8, 12)

F(2,-2) = (2+8, -2+4) = (10, 2)

Dilation: (x,y) to (1/2x, 1/2y) centered at (0,0)

D" = (2, 8) to 1/2(2), 1/2(8) = (1, 4)

E" = (8, 12) to 1/2(8), 1/2(12) = (4, 6)

F" = (10, 2) to 1/2(10), 1/2(2) = (5, 1)

The coordinates of the vertices of the final image are D''(1, 4), E"(4, 6) and F"​(5, 1)

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